Empirical Formula Calculator

Determine empirical formula from percent composition or mass data of elements in compounds

What is an Empirical Formula?

An empirical formula represents the simplest whole-number ratio of atoms of each element in a compound. Unlike molecular formulas that show the actual number of atoms, empirical formulas show the lowest ratio. For example, glucose has a molecular formula of C₆H₁₂O₆, but its empirical formula is CH₂O (a 1:2:1 ratio).

Key Difference:

  • Empirical Formula: Simplest ratio (CH₂O)
  • Molecular Formula: Actual number of atoms (C₆H₁₂O₆)
  • Relationship: Molecular formula = (Empirical formula) × n

How to Calculate Empirical Formula

  1. Convert to mass: If given percentages, assume 100g sample
  2. Convert mass to moles: Divide each element's mass by its atomic mass
  3. Find smallest mole value: Identify the element with the fewest moles
  4. Divide by smallest: Create mole ratios by dividing all by the smallest
  5. Multiply to whole numbers: If ratios aren't whole numbers, multiply all by the same factor
  6. Write formula: Use the whole number ratios as subscripts

Worked Example: Unknown Compound

Problem:

A compound is analyzed and found to contain 40.00% carbon, 6.71% hydrogen, and 53.29% oxygen by mass. What is its empirical formula?

Step 1: Assume 100g sample

• C: 40.00g
• H: 6.71g
• O: 53.29g

Step 2: Convert to moles

• C: 40.00g ÷ 12.011 g/mol = 3.331 mol
• H: 6.71g ÷ 1.008 g/mol = 6.657 mol
• O: 53.29g ÷ 15.999 g/mol = 3.331 mol

Step 3: Divide by smallest (3.331)

• C: 3.331 ÷ 3.331 = 1.000
• H: 6.657 ÷ 3.331 = 1.998 ≈ 2
• O: 3.331 ÷ 3.331 = 1.000

Step 4: Write formula

The ratios are 1:2:1, so the empirical formula is CH₂O

Answer: The empirical formula is CH₂O (empirical mass = 30.026 g/mol)

Note: This could be the empirical formula for formaldehyde (CH₂O), acetic acid (C₂H₄O₂), glucose (C₆H₁₂O₆), or any other compound with this ratio.

Common Decimal to Whole Number Conversions

When mole ratios aren't whole numbers, multiply all ratios by the appropriate factor:

x.5
multiply by 2
1.5 → 3
x.33 / x.67
multiply by 3
1.33 → 4
x.25 / x.75
multiply by 4
1.25 → 5
x.2 / x.4 / x.6 / x.8
multiply by 5
1.2 → 6

Real-World Applications

Pharmaceutical Research

When discovering new compounds, chemists use elemental analysis to determine empirical formulas before identifying the complete molecular structure.

Material Science

Analyzing unknown materials or verifying the composition of synthesized compounds in research and quality control.

Environmental Chemistry

Identifying pollutants and contaminants through combustion analysis and elemental composition studies.

Academic Learning

Essential concept in general chemistry courses for understanding molecular composition and stoichiometry.

Note: This calculator determines the empirical formula only. To find the molecular formula, you need the compound's molar mass. The molecular formula is always a whole number multiple of the empirical formula.

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