Molality Calculator
Calculate molality, moles, and solvent mass for colligative properties and solution chemistry
Molality
Calculation Steps
Additional Information
🌡️ Colligative Properties (for water solvent)
Note: These calculations assume ideal solution behavior and non-electrolyte solutes. For electrolytes, multiply molality by the van't Hoff factor (i).
📋 Solution Preparation Instructions
What is Molality?
Molality (m) is a measure of solution concentration defined as the number of moles of solute per kilogram of solvent. Unlike molarity, which depends on the volume of solution, molality is based on mass and therefore does not change with temperature. This makes molality particularly useful for studying colligative properties and temperature-dependent phenomena.
Molality Formula:
m = nsolute / masssolvent
m = (masssolute / MW) / masssolvent
- • m = Molality (mol/kg)
- • nsolute = Moles of solute (mol)
- • masssolvent = Mass of solvent (kg)
- • masssolute = Mass of solute (g)
- • MW = Molecular weight (g/mol)
Molality vs. Molarity
| Property | Molality (m) | Molarity (M) |
|---|---|---|
| Definition | mol solute / kg solvent | mol solute / L solution |
| Units | mol/kg or m | mol/L or M |
| Temperature Dependence | Independent (mass-based) | Dependent (volume changes with T) |
| Best For | Colligative properties, high temperatures | Reactions, titrations, laboratory work |
| Ease of Preparation | Requires weighing solvent | Easier with volumetric glassware |
Colligative Properties and Molality
Colligative properties depend on the concentration of solute particles, not their identity. Molality is the preferred concentration unit for these calculations because it's temperature-independent.
Freezing Point Depression
ΔTf = Kf × m × i
- • ΔTf = Freezing point depression (°C)
- • Kf = Cryoscopic constant (1.86 °C·kg/mol for water)
- • m = Molality (mol/kg)
- • i = van't Hoff factor (1 for non-electrolytes)
Example: 1 m solution lowers water's freezing point by 1.86°C
Boiling Point Elevation
ΔTb = Kb × m × i
- • ΔTb = Boiling point elevation (°C)
- • Kb = Ebullioscopic constant (0.512 °C·kg/mol for water)
- • m = Molality (mol/kg)
- • i = van't Hoff factor (1 for non-electrolytes)
Example: 1 m solution raises water's boiling point by 0.512°C
Osmotic Pressure
π = i × m × ρ × R × T
- • π = Osmotic pressure (atm)
- • ρ = Density of solution (kg/L)
- • R = Gas constant (0.08206 L·atm/mol·K)
- • T = Temperature (K)
Note: Often approximated using molarity for dilute solutions
Vapor Pressure Lowering
ΔP = Xsolute × P°solvent
- • ΔP = Vapor pressure lowering
- • Xsolute = Mole fraction of solute
- • P°solvent = Vapor pressure of pure solvent
Raoult's Law: Psolution = Xsolvent × P°solvent
Worked Examples
Example 1: Calculate Molality
Problem: What is the molality of a solution prepared by dissolving 117 g of NaCl (MW = 58.44 g/mol) in 1000 g of water?
Step 1: Calculate moles of solute
n = mass / MW = 117 g / 58.44 g/mol = 2.002 mol
Step 2: Convert solvent mass to kg
masssolvent = 1000 g × (1 kg / 1000 g) = 1.000 kg
Step 3: Calculate molality
m = n / masssolvent = 2.002 mol / 1.000 kg = 2.002 m
Answer: 2.002 m (molal)
Example 2: Freezing Point Depression
Problem: What is the freezing point of a 2.0 m aqueous solution of glucose (non-electrolyte)?
Step 1: Use freezing point depression formula
ΔTf = Kf × m × i
Step 2: Substitute values
ΔTf = 1.86 °C·kg/mol × 2.0 mol/kg × 1 = 3.72 °C
Step 3: Calculate new freezing point
Tf = 0.00 °C - 3.72 °C = -3.72 °C
Answer: The solution freezes at -3.72 °C
Example 3: Mass of Solute Needed
Problem: How many grams of NaCl (MW = 58.44 g/mol) are needed to prepare a 1.5 m solution in 500 g of water?
Step 1: Convert solvent to kg
masssolvent = 500 g × (1 kg / 1000 g) = 0.500 kg
Step 2: Calculate moles needed
n = m × masssolvent = 1.5 mol/kg × 0.500 kg = 0.75 mol
Step 3: Calculate mass
mass = n × MW = 0.75 mol × 58.44 g/mol = 43.83 g
Answer: 43.83 g NaCl
Common Applications of Molality
Antifreeze Solutions
Calculating the concentration of ethylene glycol needed to prevent engine coolant from freezing at specific temperatures uses molality and freezing point depression.
Road Salt Calculations
Determining how much salt to use for de-icing roads based on desired freezing point depression of water/ice mixtures.
Molecular Weight Determination
Using freezing point depression or boiling point elevation to experimentally determine the molecular weight of unknown compounds.
High-Temperature Chemistry
For reactions or processes occurring at elevated temperatures where volume changes significantly, molality provides temperature-independent concentration values.
Biological Systems
Studying osmotic pressure and water movement in cells and tissues, especially in physiological temperature ranges.
Food Science
Calculating sugar concentrations in preserves and jams, or salt in brines, where boiling point elevation and preservation are important.
References
Molality calculations and colligative property formulas are based on fundamental physical chemistry principles:
Note: This calculator assumes ideal solution behavior. Real solutions, especially concentrated ones or those with strong solute-solvent interactions, may deviate from ideal behavior. Colligative property calculations use standard constants for water at 1 atm pressure. For electrolytes, remember to multiply by the van't Hoff factor (i) which accounts for ion dissociation.
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